DUE THURSDAY, AUGUST 28:
In order to be able to do geometry, we need a common set of
definitions. Definitions are important
because all results depend on the definition used. It is often possible that more than one
definition is acceptable.
- Write
definitions for square, rectangle, quadrilateral, parallelogram, rhombus,
kite, and trapezoid. Make your
definition as formal and clear as possible. Be prepared to discuss why you chose
your definition, and what you think makes a good definition.
- A goat
is tied to a post on the outside of a barn using a chain. The barn has a square base. All around the barn is a field of
grass. How much grazing area does
the goat have? Notice that this
problem is very open-ended. Many
details are missing. Begin by
making up some special numbers or cases, but try to expand your solution
to cover as many possibilities as you can; try to make a completely
general solution.
DUE TUESDAY, SEPTEMBER 2
- Write
definitions for scalene, isosceles, and equilateral triangle, and for
circle.
- Euclidean
geometry is named for the Greek mathematician Euclid. Euclidean geometry is the type of
geometry studied in high school, and the type of geometry we will focus on
for the first 8 weeks or so of this course. One important feature of Euclidean
geometry is known as Euclid’s
Fifth Postulate, or the Parallel Postulate. A postulate is not something that can be
proven; it is something that is accepted as true. All mathematics is built on certain definitions
and postulates. They are the basic
building blocks of every system of mathematics. One way to state the Parallel Postulate
is: If a third line crosses two
other lines, and the interior angles on the same side of the third line
have an angle sum less than 180 degrees, then the lines, if extended
sufficiently, meet on the side in which the angle sum is less than 180
degrees.
- Explain
why this is called the Parallel Postulate.
- Draw
a diagram to illustrate the postulate as it is stated. Then rewrite the postulate in your own
words.
- It is
known that the Parallel Postulate is equivalent to the following
statement: The angle sum of the
three angles of a triangle is 180 degrees. Prove the equivalence. (Note that this requires doing two
proofs.)
DUE THURSDAY, SEPTEMBER 4
- Define
vertical angles, and prove that vertical angles are congruent.
- As a
consequence of the Parallel Postulate, what can you state about the angles
formed by two parallel lines which are crossed by a third line? Include a diagram. Prove all your assertions.
- What
does the word “is” mean? Look at
the following examples:
- A
square is a rectangle.
- A
scalene triangle is a triangle with no two sides having a common length.
- An
equilateral triangle is isosceles.
- A
square is a rhombus.
Describe how the word “is” is used
in each example above. Does “is” always
have the same meaning? How could some or
all of the examples be reworded to be clearer?
DUE TUESDAY, SEPTEMBER 9
- Define
congruence. You may start by
writing a definition that is specific to the item being considered, for
instance, “Two triangles are congruent if …” but you should then try to
find a definition that covers congruence of all kinds.
- Define
transformation, and the three kinds of transformation: reflection, rotation, and
translation. How are these related
to congruence?
- In
order to study translations, we will want to consider the plane as having
the coordinates (x, y). Suppose
that T is a function which is also a translation. Describe T in terms of coordinates. Do the same for the case where T is a
reflection across the x-axis, and the case where T is a rotation around
the origin by an angle α.
- Define
ellipse, hyperbola, and parabola.
-
- Write
the distance formula for two points in the plane.
- Define
circle.
- Write
the usual (x, y) equation-description of a circle.
- How
does your answer to (c) fit with your answer to (b)?
DUE THURSDAY, SEPTEMBER 11
- This
is really a continuation of problem 10.
We want to consider more general types of transformations.
- Build
upon your solution to number 10 and describe, in terms of coordinates, a
function T which is a rotation, but not necessarily around the origin.
- Describe,
in terms of coordinates, a function T which is a reflection across a line
other than the x-axis.
-
- A
congruence transformation will be any transformation that preserves
congruence; such a transformation is also called an isometry. Define what it means for a
transformation to be an isometry.
- Prove
that any translation is an isometry.
- Prove
that the transformation T(x, y)=(x+5, 2y) is an isometry or show that it is not an
isometry.
- What
happens to the plane (or objects in the plane, if you prefer) if you
perform two reflections? Make your
answer as complete as possible, and include proofs.
DUE TUESDAY, SEPTEMBER 16
- Can the
following definition of line be extended to three dimensions? Explain clearly. A line is a set of points of the form
{(x, y)| ax + by = c, where a, b, and c are real numbers, and a^2 + b^2 ≠
0}.
- What
happens to the plane if you perform three reflections? Give a complete answer with proofs.
- Ellipses,
hyperbolae, parabolas, and circles are all examples of conics. In general, a conic in the plane can be
written in the form (*) ax^2+bxy+cy^2+dx+ey+f=0, with a, b, c, d, e, ,f, real numbers.
- What
are the “usual” forms that you see for equations of parabolas, ellipses,
and hyperbolae?
- Find
a criterion for determining when an equation of the form (*) is a circle,
a parabola, an ellipse, or a hyperbola? [Hint: Use transformations to help you.]
DUE THURSDAY, SEPTEMBER 25
(Problem 18 continued)
We saw that if, in the equation for 18, b = 0, then we have criteria for
determining when the equation describes an ellipse, a circle, a hyperbola, or a
parabola. We want to figure out what to
do when b ≠ 0, but we will take our time developing an answer to this
question. Part (c) is the beginning of
an answer.
- Rather
than try to solve this problem by looking at what to do with b, let us
work from the other direction. We
will produce some equations which have b ≠ 0. One form for an ellipse is (1) x^2/a^2
+ y^2/b^2=1 (do not confuse the b here with the one above). This describes any ellipse with foci
aligned either horizontally or vertically and centered at the
origin. What if we want to move
the ellipse away from the origin?
The solution is to translate the ellipse. If we want the ellipse to be centered
at (h, k), then we are translating by h in the x-direction and k in the
y-direction. If the new
coordinates after translation are (x’, y’), then (x’, y’) = (x + h, y +
k), or, equivalently, (x’ – h, y’ – k) = (x, y). The original coordinates satisfied
equation (1) above, so what equation do the new coordinates satisfy?
- Now,
rather than translate the ellipse, we are interested in rotating the
ellipse. We will use Alex’s form
of the rotation equations. Start
from equation (1). If we rotate
the ellipse which is described in (x, y) coordinates by equation (1)
around the origin by an angle α, and call the new coordinates (x’’,
y’’), then (x’’, y’’) = (x cos α – y sin
α, x sin α + y cos α). As in (c), we need to solve for x and y
in terms of x’’ and y’’. Remember
that since the new coordinates were obtained from the old ones by a
rotation by α, the old ones can be obtained from the new ones by
rotation by –α. Therefore, (x’’ cos (-α)
– y’’ sin (-α), x’’ sin (-α) + y’’ cos
(-α)) = (x, y). Substitute x
and y in equation (1) with the new coordinates to obtain the equation for
the rotated ellipse. Simplify the
equation by multiplying out and getting the equation in the form of
(18).What are the values of the coefficients of x^2, xy,
y^2, x, y, and the constant term in terms of a, b, and sin(α)
and cos(α)? Notice that you need to simplify the sines and cosines using sin(-α)
= -sin(α) and cos(-α) = cos(α).
What relation(s), if any, do the coefficients of x^2, xy, and y^2 satisfy?
This is our first example of a conic with a nonzero coefficient of
xy, i.e., with b ≠ 0.
- Conics
received their name because they are the intersections of cones (in 3
dimensions) with planes. The equation
of a cone in 3 dimensions is z^2=x^2+y^2.
We know from a recent discussion that the equation of a plane in
three dimensions is ax + by + cz
+ d = 0. If a cone and a plane
intersect, then any point (x, y, z) on the
intersection must satisfy both the plane equation and the cone
equation. Solve for one of the
variables x, y, or z in the plane equation and plug it into the cone
equation. This is the general form
of the intersection. Now try some
special cases: look at planes cz + d = 0 with some
particular c and d values, if you like; look at planes where one or more
of the constants a, b, c, or d are 0 (there are many different cases
here); then look at some planes with all of the constants nonzero. In each case, discuss what shape the
intersection gives you.
-
- Prove
that reflections preserve distance, that is, if r is a reflection map, d
denotes distance, and P and Q are two points in the plane, then d(P,Q)=d(r(P), r(Q)).
We will use this later.
- What
is the result of performing 2 reflections across lines l1 and l2 in the
plane? There are three possible
cases for the two lines of reflection:
l1 and
l2 are
identical, they are parallel to each other, or they intersect. In the first case, reflecting twice
across the same line puts all the points back where they started. If the lines are parallel, the result
is a translation. Try at least two
examples to convince yourself that this works. Then determine exactly what translation
results from reflecting across l1:
ax + by = c and then l2: ax + by = c’, where a, b, c, and c’ are
fixed real numbers. You may need
to use one of our formulas for the coordinate change caused by a
reflection, or you can find a way around this.
- If
the lines are transverse, that is, if they intersect, then the result of
doing the two reflections is equivalent to a rotation. Try a couple of examples and see if you
believe this is true (I might not be as trustworthy as I look). In fact, the rotation you get is a
rotation around the intersection point of the two lines, and is a
rotation by an angle equal to twice the angle from l1 to l2. Here is how we will prove this
assertion: Let X be the point of intersection of our two lines. Let A be an arbitrary point in the
plane (we will need to do several different cases for A), let A’ be its
image after reflection about l1,
and let A’’ be the image of A’ after reflection about l2. Notice that the image of X after each
reflection is itself; X is a fixed point of the reflections. Since, by 19(a), reflections preserve
distance, then d(X,A) = d(X, A’) = d(X, A’’). Since X is fixed and A
and A’’ are two points at the same distance from X, they are on a
circle centered at X. This proves
that the two reflections result in a rotation (you may want to spend a
moment considering how that proves it).
It remains to show that the angle of rotation is the angle I
claimed above. This is your
job. Try all possible cases for
the location of A: A may be on either
line, or it may be between the lines in one of a couple of different
ways. Draw a diagram and find the
angle.
- Now
we are ready for three reflections.
There are many cases, but there are only two different kinds of
end results. Depending on the original
three lines’ position relative to each other, three reflections result in
either a reflection or what’s known as a glide reflection—a reflection
followed by a translation. The
most commonly cited example of a glide reflection is an idealized set of
footprints, with two symmetric feet leaving tracks equidistant from a
fixed line. Your job is to
determine which positions give you a reflection and which positions give
you a glide reflection. There are
many cases. Be systematic and try
to analyze each one.
DUE TUESDAY, SEPTEMBER 30
- The
last case to consider is four reflections.
The composite of four reflections is either a translation or a
rotation. I will not ask you to
work through this case. As a result
of all this, it turns out that any number of reflections is equivalent to
either a reflection, rotation, translation, or glide reflection. From here, there’s a short leap to prove
the Theorem: Every
distance-preserving transformation T is a composite of reflections.
We have done much of the work of
proving this theorem. I am not going to
ask you to complete the proof. Instead,
we will turn to the idea of congruence.
We need some definitions: A
function T which is 1-1 and has the plane as both its domain and codomain is called a transformation.
Two objects A and B in the plane will be
said to be congruent (A is congruent
to B) if there is a transformation T, which preserves distance, and with T(A) = B. Prove that congruence is an equivalence relation by
going through the steps below:
- Reflexive:
Show that A is congruent to
A. This amounts to finding an
appropriate transformation to satisfy the definition above.
- Symmetric: Show that if A is congruent to B, then
B is congruent to A.
- Transitive: Show that if A is congruent to B, and B is congruent to C, then A is congruent to C.
- Compare
these definitions for “line” in three dimensions. Alex’s Calculus definition: a line is the set of all points (x, y,
z) = (x0 + ta, y0 + tb, z0 + tc) for some t є R, where x0, y0, z0, a, b,
and c are all fixed real numbers.
Intersection of Planes definition:
a line is the set of all point (x, y, z) such that ax + by + cz + d = 0 and ex + fy + gz + h = 0, where a, b, …, h
are all fixed real numbers, and the planes are not identical and not
parallel.
- Given
x0, y0, z0, a, b, and c, find two planes
(that is, find appropriate coefficients a through h) such that the
intersection is the line in the AC definition.
- Is
your answer to (a) the only possible answer?
- Given
two planes (and hence the coefficients a through h), find the six numbers
x0, y0, z0, a, b, and c that fit the AC
definition. Hence the definitions
are equivalent.
DUE THURSDAY, OCTOBER 2
- Now
that we have determined what congruence means, we will spend some time
focusing on proving congruence is what we think it is.
- Prove
that two line segments AB and CD having the same length are
congruent. (Find the appropriate
transformation.)
- Prove
that two angles with the same measure are congruent.
- Prove
SAS triangle congruence.
- A
farmer, standing at point A, wants to fill her bucket of water and deliver
the water to the horse trough at point B.
The farm is along one side of a straight river, so the farmer needs
to walk over to the river, fill the bucket, and take it to the trough. Find the shortest path from point A, to
any part of the river, to point B.
- Conics
again: Find planes that, when
intersected with the cone z^2 = x^2 + y^2, will give you (1) a circle, (2)
an ellipse, (3) a hyperbola, (4) a parabola, (5) intersecting straight
lines, (6) a single straight line, and (7) a single point. Discuss your approach to solving each of
these cases.
DUE TUESDAY, OCTOBER 7
- Prove
ASA congruence for triangles. A
suggestion: Aim to map the included
side (the “S” in ASA) onto its corresponding side in the other triangle.
- Show
that with SSA, there can be two different, incongruent triangles which
both satisfy SSA.
- Prove
or disprove: If in quadrilaterals
ABCD and EFGH, angles A, C, E and G are right angles, AB = EF, and BC = FG, then the quadrilaterals are congruent.
DUE THURSDAY, OCTOBER 9
- We
will repeat the steps of 18(c-d) for parabolas. Follow the steps below.
- Take
the equation y=ax^2 and find its image after translation by (h, k).
- Find
its image after rotation by α.
- As a
new step, take the rotated parabola and translate it by (h,k).
- If
the parabola is rotated by an angle of 3π/4 radians, what equation
should you get? (This is a familiar algebra II equation.) Verify your answer by using α =
3π/4 in your solution to (b).
- Right
triangles
- The
Pythagorean Theorem states that if ABC is a right triangle with legs of
length a and b, and a hypotenuse of length c,
then a2 + b2 = c2. Prove the Pythagorean Theorem. (I will be disappointed if, as a class,
we come up with less than 3 proofs of this theorem. I will give you one diagram in class
which suggests one possible proof.)
- Show
with a diagram how any triangle (acute, obtuse) can be seen as a sum of
two right triangles, and in the case of the obtuse triangle, can also be
seen as the difference of two right triangles.
- What
is the formula for the area of a triangle?
- In
measuring length, the unit of length is 1 inch, 1 foot, etc, or 1cm, 1m,
1km, etc. In what units is area
measured?
DUE TUESDAY, OCTOBER 14
- The
unit of measurement for area is a square, with length 1 unit on each side,
and having an area of 1 unit2, or 1 u2. Explain how you can derive that the area
of any rectangle is equal to bh,
where b is the length of the base and h is the height of the rectangle.
-
- Build
upon your answer to 31 to explain how the area of any right triangle is
bh/2, where b and h are the lengths of the legs of the triangle.
- For
any (not necessarily right) triangle, define base and height.
- Use
29(b) and 32(a) to show that the area of any triangle is bh/2, where b
and h are the base and height of the triangle.
- Prove
that the area of a trapezoid ABCD, with side AB parallel to side CD, is
equal to ˝ (length of AB + length of CD)×(height
of the trapezoid). You may want to
use the results of part (c).
- Define
base and height in a parallelogram.
Prove that the area of a parallelogram is bh, where b is the base and h is the height.
- The
law of cosines states that for any triangle ABC, if c=AB, b=AC, and a=BC
and C=m<ABC, then c2 = a2 + b2 – 2ab cos C. Use
29(b) to help you prove the law of cosines.
Study for Thursday’s exam.
More to come…